A.

Kayleen left home at noon and drove to boston. she got there at 4:00. if boston is about 280 miles away, what was kayleens average speed.

b. Elijah was also driving to Boston, but she left from outside of the city and was already 40 miles closer than Kayleen was when she started. She also left at noon and got there at 4:00. What was her average speed?

Question

Shelton

Mathematics

9 January, 05:16

A.

Kayleen left home at noon and drove to boston. she got there at 4:00. if boston is about 280 miles away, what was kayleens average speed.

b. Elijah was also driving to Boston, but she left from outside of the city and was already 40 miles closer than Kayleen was when she started. She also left at noon and got there at 4:00. What was her average speed?

+1

Answers (1)

Know the Answer?

Corinne Key · Answer 1

Answer: a) 70 mph

b) 80 mph

Step-by-step explanation:

Given that Kayleen left home at noon and drove to boston. she got there at 4:00. Then time spent will be 4 hours. Noon means 12pm

Distance covered = 280 miles kayleens average speed will be

Speed = distance/time

Speed = 280/4 = 70 mph

Given that Elijah was already 40 miles closer than Kayleen was when she started

Distance covered by Elijah will be

Distance = 40 + 280 = 320

Time = 4 hours

Speed = 320/4 = 80 mph