Next-door neighbors Bob and Jim use hoses from both houses to fill Bob's swimming pool. They know that it takes 22 h using both hoses. They also know that Bob's hose, used alone, takes 50% less time than Jim's hose alone. How much time is required to fill the pool by each hose alone?

Question

Averie Sanders

Mathematics

23 September, 11:43

Next-door neighbors Bob and Jim use hoses from both houses to fill Bob's swimming pool. They know that it takes 22 h using both hoses. They also know that Bob's hose, used alone, takes 50% less time than Jim's hose alone. How much time is required to fill the pool by each hose alone?

+3

Answers (1)

Know the Answer?

Olivia Wilson · Answer 1

correct answer: Bob's hose required alone 33 hours and Jim's hose required alone 66 hours

Step-by-step explanation:

Given:

Bob's hose time = 50% of Jim's hose time ⇒

⇒ Jim's hose time = 2 · Bob's hose time

Let be x Bob's hose time and 2x Jim's hose time

The following equation will solve the problem:

1/x + 1 / 2x = 1/22

The common denominator for both fractions is 2x, so we will multiply the first fraction by the number 2 and get:

2/2x + 1/2x = 1/22 ⇒ 3/2x = 1/22 ⇒ x = 3 · 22 / 2 ⇒ x = 3 · 11 = 33 hours

Bob's hose time x = 33 hours and

Jim's hose time 2x = 66 hours

God is with you!