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5 October, 22:47

If f (x) = 2x^2 + 1 and g (x) = x2 - 7, find (f + g) (x).

4x^2+1/2x-1

4x^2+3/2x-1

6x^2-7

4x^2+3/2x-7

+1
Answers (1)
  1. 5 October, 23:04
    0
    (f + g) (x) = 3x² - 6

    Step-by-step explanation:

    (f + g) (x) = f (x) + g (x)

    f (x) = 2x² + 1, g (x) = x² - 7.

    Substitute:

    (f + g) (x) = (2x² + 1) + (x² - 7) = (2x² + x²) + (1 - 7) = 3x² - 6
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