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Freddy Goodman
Mathematics
30 November, 05:47
Whats x^2-2x-2
akjdcpiwhbfcnkluje
+1
Answers (
2
)
Mylee Lee
30 November, 05:57
0
Step-by-step explanation:
1 In general, given a{x}^{2}+bx+cax
2
+ bx+c, the factored form is:
a (x-/frac{-b+/sqrt{{b}^{2}-4ac}}{2a}) (x-/frac{-b-/sqrt{{b}^{2}-4ac}}{2a
2a
-b+√
b
2
- 4ac
) (x-
2a
-b-√
b
2
- 4ac
)
2 In this case, a=1a=1, b=-2b=-2 and c=-2c=-2.
(x-/frac{2+/sqrt{{ (-2) }^{2}-4/times - 2}}{2}) (x-/frac{2-/sqrt{{ (-2) }^{2}-4/times - 2}}{2}) (x-
2
2+√
(-2)
2
- 4*-2
) (x-
2
2-√
(-2)
2
- 4*-2
)
3 Simplify.
(x-/frac{2+2/sqrt{3}}{2}) (x-/frac{2-2/sqrt{3}}{2}) (x-
2
2+2√
3
) (x-
2
2-2√
3
)
4 Factor out the common term 22.
(x-/frac{2 (1+/sqrt{3}) }{2}) (x-/frac{2-2/sqrt{3}}{2}) (x-
2
2 (1+√
3
)
) (x-
2
2-2√
3
)
5 Cancel 22.
(x - (1+/sqrt{3})) (x-/frac{2-2/sqrt{3}}{2}) (x - (1+√
3
)) (x-
2
2-2√
3
)
6 Simplify brackets.
(x-1-/sqrt{3}) (x-/frac{2-2/sqrt{3}}{2}) (x-1-√
3
) (x-
2
2-2√
3
)
7 Factor out the common term 22.
(x-1-/sqrt{3}) (x-/frac{2 (1-/sqrt{3}) }{2}) (x-1-√
3
) (x-
2
2 (1-√
3
)
)
8 Cancel 22.
(x-1-/sqrt{3}) (x - (1-/sqrt{3})) (x-1-√
3
) (x - (1-√
3
))
9 Simplify brackets.
(x-1-/sqrt{3}) (x-1+/sqrt{3}) (x-1-√
3
) (x-1+√
3
)
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Ahmed Newton
30 November, 06:02
0
x = 1±sqrt (3)
Step-by-step explanation:
x^2-2x-2=0
This polynomial does not factor, so we can use completing the square to solve.
Add 2 to each side
x^2-2x-2+2 = 2
x^2 - 2x = 2
b=-2
We take b/2 and then square it
-2/2 = - 1 then square it (-1) ^2 = 1
Add 1 to each side
x^2 - 2x + 1 = 2+1
The left side is equal to (x + (b/2)) ^2
(x-1) ^2 = 3
Take the square root of each side
sqrt (x-1) ^2 = ±sqrt (3)
x-1 = ±sqrt (3)
Add 1 to each side
x-1+1 = 1±sqrt (3)
x = 1±sqrt (3)
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