Find three consecutive integers whose sum is - 33

n, n + 1, n + 2 - three consecutive integers

-33 - the sum

Equation:

n + (n + 1) + (n + 2) = - 33

n + n + 1 + n + 2 = - 33

3n + 3 = - 33 |subtract 3 from both sides

3n = - 36 |divide both sides by 3

n = - 12

n + 1 = - 12 + 1 = - 11

n + 2 = - 12 + 2 = - 10

Answer: - 12, - 11, - 10.

X

x+1

x+2

x+x+1+x+2=-33

3x+3=-33

3x=-36

x=-12

The three consecutive integers are - 12, - 11, and - 10