Ask Question
20 December, 01:54

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=7-x^2.

What are the dimensions of such a rectangle with the greatest possible area?

+2
Answers (1)
  1. 20 December, 02:03
    0
    If the base is on the x-axis, the width of the rectangle is = xif the height is based on the parabola, the length = 7-x^2

    the area of a rectangle = length * width

    thus, area = x * (7-x^2) = 7x-x^3

    in order to maximize the area, you would need to take the derivative of the area and set it equal to 0

    Area = 7x-x^3Area' = 7 - 3x^2

    7-3x^2 = 0thus, x = 1.5275

    this x represents the x needed to create the largest possible area with the given parameters.

    Thus:Width (x-axis) = 1.5275Length (y-axis) = 7 - (1.5275) ^2 = 4.6667
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=7-x^2. What are the dimensions of such a ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers