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18 January, 10:09

Factorize a^2+b^2+2 (ab-ac-bc)

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  1. 18 January, 10:13
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    (a + b) (a + b - 2c)

    Step-by-step explanation:

    Note that

    (a + b) ² = a² + b² + 2ab

    Given

    a² + b² + 2 (ab - ac - bc) ← distribute parenthesis

    = a² + b² + 2ab - 2ac - 2bc

    = (a + b) ² - 2ac - 2bc ← factor out - 2c from each term

    = (a + b) ² - 2c (a + b) ← factor out (a + b) from each term

    = (a + b) [ a + b - 2c ]

    = (a + b) (a + b - 2c) ← in factored form
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