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1 November, 22:46

Chapter 03, Review Problems, Question 59

Two gasohol mixtures are available, one with 6.35% alcohol and the other with 11.28% alcohol. How many litres of the 6.35% mixture must be added to 27.9 L of the other mixture to make a final mixture containing 8.00% alcohol?

Round the answer to one decimal place.

L

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  1. 1 November, 23:02
    0
    The answer is 55.4 L

    x - liters of the 6.35% mixture needed

    6.35% = 0.0635

    11.28% = 0.1128

    8% = 0.08

    Liters of alcohol in 6.35% mixture is 0.0635x.

    Liters of alcohol in 11.28% mixture is: 0.1128 * 27.9 L = 3.147 L

    We need to get 8.00% mixture:

    (0.0635x + 3.147) / (27.9 + x) = 0.08

    0.0635x + 3.147 = 0.8 * (27.9 + x)

    0.0635x + 3.147 = 2.232 + 0.08x

    3.147 - 2.232 = 0.08x - 0.0635x

    0.915 = 0.0165x

    x = 0.915/0.0165

    x = 55.4 L
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