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29 December, 22:04

Solve the following system of equations algebraically:

y = x^2+7x-4

y = - x-4

+2
Answers (2)
  1. 29 December, 22:18
    0
    Y=x²+7x-4

    y=-x-4

    We can solve this system of equation by equalization method.

    x²+7x-4=-x-4

    x²+7x+x-4+4=0

    x²+8x=0

    x (x+8) = 0

    we have two linear equations:

    x=0 ⇒ x=0 ⇒ y=-x-4=-0-4=-4

    (x+8) = 0 ⇒ x=-8 ⇒ y=-x-4 = - (-8) - 4=8-4=4

    We have two solutions:

    solution₁: x=0; y=-4

    solution₂: x=-8; y=4
  2. 29 December, 22:32
    0
    Y = x² + 7x - 4

    y = - x - 4

    x² + 7x - 4 = - x - 4

    + x + x

    x² + 8x - 4 = - 4

    + 4 + 4

    x² + 8x = 0

    x (x) + x (8) = 0

    x (x + 8) = 0

    x = 0 or x + 8 = 0

    - 8 - 8

    x = - 8

    y = - x - 4

    y = - 0 - 4

    y = 0 - 4

    y = - 4

    (x, y) = (0, - 4)

    or

    y = - x - 4

    y = - (-8) - 4

    y = 8 - 4

    y = 4

    (x, y) = (-8, 4)

    The solutions are (0, - 4) and (8, - 4).
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