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9 August, 19:35

Because gambling is a big business, calculating the odds of a gambler winning or losing in every game is crucial to the financial forecasting for a casino. Consider a slot machine that has three wheels that spin independently. Each has 13 equally likely symbols: 5 bars, 4 lemons, 3 cherries, and a bell. If you play once, what is the probability that you will get:

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  1. 9 August, 19:48
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    a) 0.1165

    b) 0.0983

    c) 0.000455

    d) 0.787

    e) 0.767

    Step-by-step explanation:

    5 bars, 4 lemons, 3 cherries, and a bell

    Total = 5+4+3+1 = 13

    The probability of getting a bar on a slot, P (Ba) = 5/13 = 0.385

    A lemon, P (L) = 4/13 = 0.308

    A cherry, P (C) = 3/13 = 0.231

    A bell, P (Be) = 1/13 = 0.0769

    a) Probability of getting 3 lemons = (4/13) * (4/13) * (4/13) = 256/2197 = 0.1165

    b) Probability of getting no fruit symbol

    On each slot, there are 4+3 = 7 fruit symbols.

    Probability of getting a fruit symbol On a slot = 7/13

    Probability of not getting a fruit symbol = 1 - (7/13) = 6/13 = 0.462

    Probability of not getting a fruit symbol On the three slots = 0.462 * 0.462 * 0.462 = 0.0983

    c) Probability of getting 3 bells, the jackpot = (1/13) * (1/13) * (1/13) = 1/2197 = 0.000455

    d) Probability of not getting a bell on the 3 slots

    Probability of not getting a bell on one slot = 1 - (1/13) = 12/13 = 0.923

    Probability of not getting a bell on the 3 slots = (12/13) * (12/13) * (12/13) = 1728/2197 = 0.787

    e) Probability of at least one bar is a sum of probabilities

    Note that Probability of getting a bar = 5/13 and probability of not getting a bar = 8/13

    1) Probability of getting 1 bar and other stuff on the 2 other slots (this can happen in 3 different orders) = 3 * (5/13) * (8/13) * (8/13) = 960/2197 = 0.437

    2) Probability of getting 2 bars and other stuff on the remaining slot (this can also occur in 3 different orders) = 3 * (5/13) * (5/13) * (8/13) = 600/2197 = 0.273

    3) Probability of getting 3 bars on the slots machine = (5/13) * (5/13) * (5/13) = 125/2197 = 0.0569

    Probability of at least one bar = 0.437 + 0.273 + 0.0569 = 0.7669 = 0.767
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