A committee of four is chosen at random from a group of 66 women and 55 men. Find the probability that the committee contains at least one man.

Question

Ana Lewis

Mathematics

24 November, 17:05

A committee of four is chosen at random from a group of 66 women and 55 men. Find the probability that the committee contains at least one man.

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Raphael Stevenson · Answer 1

Answer: There are 13 C 4 = 715 ways to choose a group of men and women.

So there are 715 - 70 = 645 ways to choose a group with at least one man.

This means the probability is 645/715 = 129/143 = 0.9020979 (so roughly a 90.20979% chance)

Step-by-step explanation: There are 13 C 4 = 715 ways to choose a group of men and women.

So there are 715 - 70 = 645 ways to choose a group with at least one man.

This means the probability is 645/715 = 129/143 = 0.9020979 (so roughly a 90.20979% chance)