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5 April, 03:55

What is the center of the circle given by the equation (x-3) 2 + (y-9) 2 = 16?

A. (-9,-3)

B. (-3,-9)

C. (3,9)

D. (9,3)

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Answers (2)
  1. 5 April, 04:12
    0
    The center is (3,9) and the radius is 4

    Step-by-step explanation:

    We can write the equation for a circle as

    (x-h) ^2 + (y-k) ^2 = r^2

    Where (h, k) is the center and r is the radius

    (x-3) ^2 + (y-9) ^2 = 4^2

    The center is (3,9) and the radius is 4
  2. 5 April, 04:20
    0
    C

    Step-by-step explanation:

    (x-a) ^2 + (y-b) ^2 = r^2

    (a, b) = Center

    r = radius

    SO ...

    That means the center of the circle " (x-3) ^2 + (y-9) ^2 = 16" is ...

    (3,9) (C)
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