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2 February, 01:36

Derive a formula for sin (2?) in terms of sin (?) and cos (?) for all real numbers?.

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  1. 2 February, 01:49
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    Answer: sin (2α) = 2 sin (α) cos (α)

    Step-by-step explanation:

    We departure from the sin of a sum of angles

    sin (α + β) = sinα * cosβ + sinβ * cosα

    if α = β ⇒ sin (α + α) = sin (α) * cos (α) + sin (α) * cos (α)

    sin (2α) = 2 sin (α) cos (α)
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