What is the center of a circle whose equation is x2 + y2 - 12x - 2y + 12 = 0?

(-12, - 2)

(-6, - 1)

(6, 1)

(12, 2)

(6,1)

Step-by-step explanation:

Just look for the terms with x and y in them. Divide their coefficients by two, and multiply by - 1. And then put them in an ordered pair.

So in this case, - 12x - -> 6 and - 2y - -> 1

Obviously the more orthodox way would be to actually complete the square, but I'm lazy, this way is faster, and since this seems to be multiple choice, as long as you have the correct answer, it shouldn't matter.