The (amplitude/period/frequency) of y=-5sin2x is 5

Hello!

The amplitude of trigonometric functions is the maximum displacement on the graph of a function. In the case of the sine and cosine functions, this value is the leading coefficient of the function. If y = A sin x, then the amplitude is |A|.

Therefore, the amplitude of the function y = - 5sin2x, is A = 5.

The period of trigonometric functions is the displacement of x at which the graph of a function begins to repeat. The general form of the sine function is as follows: f (x) = A sin Bx, where |A| is the amplitude and B determines the period. The period is found by the equation: P = 2π/B

P = 2π/2 = π

Therefore, the period of the function y = - 5sin2x, is P = π.

The frequency of trigonometric functions are inversely related to the period of trigonometric functions. It is the number of cycles it completes in a given interval. If a general form of the sine function is f (x) = A sin Bx, then the frequency is B.

Therefore, the frequency of the function y = - 5sin2x, is B = 2.

Answers:

Amplitude = 5 Period = π Frequency = 2