A delivery of 50 transistors contains 40 good ones and 10 defectives. In a test five of them are checked. How many possibilities are there to have 3 good ones and 2 defective transistors in the test set?

0.2048

0.2048

Step-by-step explanation:

p (good transistor) = 40/50 = 4/5

p (defective transistor) = 10/50 = 1/5

the probability of having 3 good ones and 2 defective transistors in the test set:

= 5C3 * (4:5) ³ * (1:5) ²

= 0.2048