How do i factor - 4c^2+19c+5

-1 (4c+1) (c-5)

Step-by-step explanation:

First get rid of the negative by factoring out - 1, then determine what factors of 5, the constant term (the number without the x), multiply by 4 to add up to - 19. The only factors of 5 are 1 and 5, so we will use these. (4c+1) (c-5) can be "foiled" to check our answer.