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27 October, 21:40

A bucket contains 50 lottery balls numbered 1-50. one is drawn at random. Find p (multiple of 6/2-digit number)

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  1. 27 October, 21:54
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    This is a problem of conditional probability that can be calculated by the formula:

    P (B | A) = P (A ∩ B) / P (A)

    We know that:

    - between 1 and 50 there are 41 two-digit numbers, therefore

    P (A) = 41/50 = 0.82

    - between 1 and 50 there are 8 multiples of six, therefore

    P (B) = 8/50 = 0.16

    - between 1 and 50 there are 7 two-digits mutiples of six, therefore

    P (A ∩ B) = 7/50 = 0.14

    Now, we can calculate:

    P (B | A) = P (A ∩ B) / P (A)

    = 0.14 / 0.82

    = 0.17

    Therefore, the probability of getting a multiple of 6 if we draw a two-digit number is 17%.
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