A baseball catcher is performing a stunt for a television commercial. He will catch a baseball (mass 145 g) dropped from a height of 60.0 m above his glove. His glove stops the ball in 0.0100 s. What is the force exerted by his glove on the ball?

174kN

Step-by-step explanation:

F (force) = mass (m) * acceleration (a)

From equations of motion

h = ut + 1/2at^2

h = 60m, t = 0.01s, u = 0m/s

60 = 1/2*a*0.01^2

a = 60*2/1*10^-4 = 1.2*10^6m/s^2

Mass (m) = 145g = 145/1000 = 0.145kg

F = ma = 0.145*1.2*10^6 = 174000N = 174000/1000 = 174kN