What is the solution for the following system of equations? Use ANY method to solve. 2x + 8y = 4 x = - 3y + 5 Question 4 options: x = 14, y = - 3 x = 2, y = - 3 x = - 3, y = - 3 x = 12, y = 5

x = 14, y = - 3

Step-by-step explanation:

Solve the following system:

{2 x + 8 y = 4 | (equation 1)

{x = 5 - 3 y | (equation 2)

Express the system in standard form:

{2 x + 8 y = 4 | (equation 1)

{x + 3 y = 5 | (equation 2)

Subtract 1/2 * (equation 1) from equation 2:

{2 x + 8 y = 4 | (equation 1)

{0 x - y = 3 | (equation 2)

Divide equation 1 by 2:

{x + 4 y = 2 | (equation 1)

{0 x - y = 3 | (equation 2)

Multiply equation 2 by - 1:

{x + 4 y = 2 | (equation 1)

{0 x+y = - 3 | (equation 2)

Subtract 4 * (equation 2) from equation 1:

{x+0 y = 14 | (equation 1)

{0 x+y = - 3 | (equation 2)

Collect results:

Answer: x = 14, y = - 3