Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5in. And whose upper base is a square with a side 3in., and whose altitude is 12 in. Round your answer to the nearest hole number.

A - 196 cu in.

B - 47 cu in.

C - 1038 cu in.

D - 226 cu in.

Question

Fiona Glover

Mathematics

13 March, 09:49

Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5in. And whose upper base is a square with a side 3in., and whose altitude is 12 in. Round your answer to the nearest hole number.

A - 196 cu in.

B - 47 cu in.

C - 1038 cu in.

D - 226 cu in.

+5

Answers (1)

Know the Answer?

Caden Fields · Answer 1

The volume of the frustrum is the difference in the volumes of these two pyramids:

30 * 5^2 / 3 - 18 * 3^2 / 3

= 750/3 - 162/3

= 250 - 54

= 196 cubic inches.

You're Answer is A - 196 cu in.

Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5in. And whose upper base is a square with a side 3in., and whose altitude is 12 in. Round your answer to the nearest hole number.A - 196 cu in.B - 47 cu in.C - 1038 cu in.D - 226 cu in.

Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5in. And whose upper base is a square with a side 3in., and whose altitude is 12 in. Round your answer to the nearest hole number.

A - 196 cu in.

B - 47 cu in.

C - 1038 cu in.

D - 226 cu in.