Fifteen participants take a pretest and a posttest and have a mean change score of 1.5. The standard deviation of the comparison distribution is 0.5, what is the t score?

here t score is 3

Step-by-step explanation:

given data

total number n = 15

mean µ = 1.5

standard deviation SD = 0.5

to find out

the t score

solution

we know mean and SD

so t score will be by given formula that is

t score = mean / SD ... 1

put here value mean and SD in equation 1

t score = 1.5 / 0.5

t score = 3

so here t score is 3