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15 April, 17:28

Mike went to a football game with his family. They bought 5 boxes of popcorn and 3 programs, and spent $41. Sean's family went to the same game, bought 3 boxes of popcorn and 2 programs, and spent $26. How much does each program cost at the game? How do I solve this?

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  1. 15 April, 17:46
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    EZ!

    Let's say each box costs $X and each program costs $Y

    Thus, Mike's family spent:

    $ (5X+3Y)

    or

    $41

    Sean's family spent

    $ (3X+2Y)

    or

    $26

    This yields us a system of two equations:

    5x+3y=41

    3x+2y=26

    5x+3y=41

    2y=26-3x

    5x+3y=41

    y=13-1.5x

    5x+3 (13-1.5x) = 41

    y=13-1.5x

    5x+39-4.5x=41

    y=13-1.5x

    0.5x+39=41

    y=13-1.5x

    0.5x=2

    y=13-1.5x

    x=4

    y=13-1.5x

    x=4

    y=7

    Each box costs $4 and each program costs $7
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