What are the solutions of

-x^2+4x=x-4?

A. - 5 and 0

B. - 5 and - 1

C. - 1 and 4

D. 0 and 4

-x^ 2 + 4x = x - 4

-x^2 + 3x + 4 = 0

multiply through by - 1:-

x^2 - 3x - 4 = 0

factoring:-

(x - 4) (x + 1) = 0

x = 4 and - 1

C

I like the coefienti in front of 2nd degree to be positive

times - 1

x^2-4x=-x+4

add x to both sides and minus 4 from both sides

x^2-3x-4=0

factor

what 2 numbers multiply to get - 4 and add to get - 3?

-4 and 1

(x-4) (x+1) = 0

set to zero

x-4=0

x=4

x+1=0

x=-1

-1 and 4

C is answer