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Carson Ellison
Mathematics
29 April, 13:59
Name the focus of y = 0.6x^2.
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Cristina Ewing
29 April, 14:15
0
Parabola
remember that
parabola equation is
4p (y-k) = (x-h) ^2 for a verticl parabola
p=distance from vertex to focus and from vertex to directix
solve for p, k, h
y=0.6x^2
4p (y-0) = (x-0) ^2
divide both sides by 4p
(y-0) = 1/4p times (x-0) ^2
y=0.6x^2
1 / (4p) = 0.6
find p
multiply 4p
1=2.4p
divide 2.4
1/2.4=p
h=0, k=0
vertex=0,0
opens up so go up to find focus
(0,0)
0+1/2.4=1/2.4
focus is at (0,1/2.4)
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