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9 November, 10:47

A country's population in 1993 was 171 million. In 1999 it was 176 million. Estimate the population in 2012 using the exponential growth formula. Round your answer to the nearest million.

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  1. 9 November, 12:46
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    This is the concept of application of an exponential growth functions. This question can be modeled using the exponential formula;

    f (t) = ae^ (kt)

    where;

    a=initial population

    f (x) = current population

    t=time

    k=constant of proportionality

    suppose the time at 1993 is t=0 and time in 1999 is t = 6

    N/B. The population is in millions;

    Thus;

    176=171e^ (6t)

    176/171=e^ (6t)

    introducing the natural logs we getL

    6t=ln (176/171)

    t=1/6ln (176/171)

    t=0.0048

    Hence;

    f (t) = 171e^ (0.0048t)

    Therefore the population in 2012 will be:

    t=19

    thus;

    f (t) = 171e^ (0.0048*19)

    f (t) = 187.33

    Thus, the population will be given by:

    f (t) = 187 million
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