In one town, 79% of adults have health insurance. what is the probability that 4 adults selected at random from the town all have health insurance? round to the nearest thousandth if necessary.

The number may be calculated as (0.79) ^4 = 0.3895 ≈ 0.400.

This is becasue the probability of finding each adult having health insurance is independent of others.

When, events are independent, the combined probability is the product of each probability = >

Probailibty of one adult with healt insurance * probability of one adult with healt insurance * probability of one adult with health insurance * probability of one adult with health insurance = 0.79 * 0.79 * 0.79 * 0.79 = (0.79) ^4.

Answer: 0.400