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9 August, 01:44

Factor completely 9x^4y - 6x^3y^2 + 3x^2y^3.

A-3x^2y (3x^2 - 2xy + y^2

B-3xy (3x^2 - 2xy + y^2

C-3xy^2 (3x^2 - 2xy + y^2

D-3x^2y (3x^2 + 2xy + y^2

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Answers (1)
  1. 9 August, 02:01
    0
    The answer is A because if you factor out 3x^2y, you get 3x^2 - 2xy + y^2 and you cannot factor that out anymore
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