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16 June, 19:17

Virus A will damage the system with probability 0.3. Independently of it, virus B will damage the system with probability 0.5. Independently of A and B, virus C will damage the system with probability 0.6. What is the probability that the system will be damaged (by at least one of the viruses) ?

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  1. 16 June, 19:36
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    0.86.

    Step-by-step explanation:

    Probability (None of the viruses will do any damage) = (1 - 0.3) (1-0.5) (1-0.6)

    = 0.14.

    Therefore the probability that at least one will do damage = 1 - 0.14 = 0.86.
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