Solve using the best method:

A football is punted into the air. Its height

h, in meters, after t seconds is given by the

equation h = - 4.912 + 24.5t + 1. When

does the ball hit the ground?

Step-by-step explanation:

Question not written well

The equation of the ball is meant to be in a parabola or trajectory form.

So, h = - 4.912t² + 24.5t + 1

The ball will hit the ground when the height is 0

I. e. h = 0

Therefore,

-4.912t² + 24.5t + 1 = 0

Using almighty formula,

a = - 4.912 b = 24.5 c = 1

t = (-b±√b²-4ac) / 2a

t = (-24.5±√24.5²-4*-4.912 * 1) / 2 * - 4.912

t = (-24.5±√600.25 + 19.648) / 9.824.

t = (-24.5 ± 24.898) / 9.824

So,

t = (-24.5 + 24.898) / 9.824

t = 0.398 / 9.824

t = 0.04seconds

Or

t = (-24.5 - 24.898) / 9.824

t = - 5.03 seconds

So, we are going to discard the negative time,

t = 0.04 second is the correct time the ball will hit the ground

Answer: After 5.02 seconds

Step-by-step explanation:

The correct equation in the question is h = - 4.912 t² + 24.5t + 1

Hi, when the ball hits the ground, height = 0.

So, replacing in the equation:

0 = - 4.912 t² + 24.5t + 1

For: ax2 + bx + c

x = [ - b ± √b²-4ac] / 2a (quadratic formula)

Replacing with the values given:

x = [ - 24.5 ± √24.5²-4 (-4.912) 1] / 2 (-4.912)

x = [ - 24.5 ± √600.25+19.648] / -9.824

x = [ - 24.5 ± √619.898] / -9.824

x = [ - 24.5 ± 24.90] / -9.824

Positive:

x = [ - 24.5 + 24.90 ] / -9.824 = - 0.04 seconds

Negative:

x = [ - 24.5 - 24.90] / -9.824 = 5.02 seconds

Since time can't be negative, the answer is 5.02 seconds.

Feel free to ask for more if needed or if you did not understand something.