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26 June, 04:25

Write an equation of a parabola with a vertex at the origin and a directx at y=5

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  1. 26 June, 04:47
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    Directrix at y=5 (horizontal line) → The parabola is vertical

    Vertex at the orgin: V = (0,0) = (h, k) →h=0, k=0

    The directix is above the vertex→the parabola opens downward→p is negative

    p is the distance between the vertex and the directrix→p=-5

    Equation has the form:

    (x-h) ^2=4p (y-k)

    (x-0) ^2=4 (-5) (y-0)

    x^2=-20y
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