Derive the equation of the parabola with a focus at (-7, 5) and a directrix of y = - 11.

f (x) = one thirty second (x + 7) 2 - 3

f (x) = - one thirty second (x + 7) 2 - 3

f (x) = - one thirty second (x - 7) 2 - 3

f (x) = one thirty second (x - 7) 2 - 3

Question

Kyle

Mathematics

11 October, 20:33

Derive the equation of the parabola with a focus at (-7, 5) and a directrix of y = - 11.

f (x) = one thirty second (x + 7) 2 - 3

f (x) = - one thirty second (x + 7) 2 - 3

f (x) = - one thirty second (x - 7) 2 - 3

f (x) = one thirty second (x - 7) 2 - 3

+3

Answers (1)

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Reilly Benjamin · Answer 1

In this problem, given the focus at (-7,5) and directrix at y = - 11. then it is implied that the parabola is facing upwards. The vertex hence is at the middle of the focus and the directrix, hence at (-7, - 3). The general formula of the parabola is y-k = 4a (x-h) ^2. SUbstituting, y + 3 = 1/30 * (x+7) ^2. Answer i sA.

Derive the equation of the parabola with a focus at (-7, 5) and a directrix of y = - 11.f (x) = one thirty second (x + 7) 2 - 3f (x) = - one thirty second (x + 7) 2 - 3f (x) = - one thirty second (x - 7) 2 - 3f (x) = one thirty second (x - 7) 2 - 3

Derive the equation of the parabola with a focus at (-7, 5) and a directrix of y = - 11.

f (x) = one thirty second (x + 7) 2 - 3

f (x) = - one thirty second (x + 7) 2 - 3

f (x) = - one thirty second (x - 7) 2 - 3

f (x) = one thirty second (x - 7) 2 - 3