A graph of the function g (x) = x^4-8x³+x²+42x has zeros at - 2, 0, 3 and 7. What are the signs of the values between 0 and 3? Show algebraically how you know.
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Home » Mathematics » A graph of the function g (x) = x^4-8x³+x²+42x has zeros at - 2, 0, 3 and 7. What are the signs of the values between 0 and 3? Show algebraically how you know.