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A graph of the function g (x) = x^4-8x³+x²+42x has zeros at - 2, 0, 3 and 7. What are the signs of the values between 0 and 3? Show algebraically how you know.

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  1. 26 May, 00:07
    0
    The answer to your question is Positive

    Step-by-step explanation:

    Function

    g (x) = x⁴ - 8x³ + x² + 42x

    To know if the function is positive or negative in the interval (0, 3), look for two numbers between this interval and evaluate the function.

    The numbers I chose were 1 and 2

    - g (1) = (1) ⁴ - 8 (1) ³ + (1) ² + 42 (1)

    = 1 - 8 - 1 + 42

    = + 36 positive

    - g (2) = (2) ⁴ - 8 (2) ³ + (2) ² + 42 (2)

    = 16 - 64 + 4 + 84

    = + 40

    Conclusion

    The function is positive in the interval (0, 3)
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