Approximate the area under the function between a and b using a left hand sum with the given number of intervals.

f (x) = x^2

a=0 b=4 4 intervals

The length of each interval is (b-a) / i where i=number of intervals, a=starting value and b=ending value

so (4-0) / 4=4/4=1

each interval is 1 unit in width

ok

the values of the heights are

f (0)

f (1)

f (2)

f (3)

f (0) = 0

f (1) = 1

f (2) = 4

f (3) = 9

1 (0+1+4+9)

1 (14)

14 is the aproximate area under the curve from a=0 to a=4