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4 February, 20:15

For a convex 41-gon, what is the sum of the measures of the interior angles?

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  1. 4 February, 20:44
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    Given:

    convex 41-gon

    n = 41

    Required:

    Sum of interior angles.

    Solution:

    To solve for the sum of interior angles, we can use the formula:

    Sum of interior angles = 180 (n-2) °

    Substituting,

    Sum of interior angles = 180 (41-2) °

    Sum of interior angles = 7020°

    Therefore, the sum of the measures of the interior angle of a convex 41-gon is 7020°.
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