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4 December, 15:56

What is the answer to y=-3x^2+12x-33 and is it a maximum value or a minimum value

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  1. 4 December, 16:16
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    maximum value

    Step-by-step explanation:

    Given a quadratic function in standard form

    y = ax² + bx + c (a ≠ 0)

    • If a > 0 then minimum value

    • If a < 0 then maximum value

    y = - 3x² + 12x - 33 ← is in standard form with a = - 3

    Since a < 0 then maximum value
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