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2 November, 06:09

A hypotenuse of a right triangle is 52 in. One leg of the triangle is 8in. more than twice the length of the other. What is the perimeter of the triangle?

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  1. 2 November, 06:17
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    c=52, a=2b+8

    Pythagorean Theorem = a^2+b^2=c^2

    (2b+8) ^2+b^2=52^2

    4b^2+32b+64+b^2=2704

    5b^2+32b-2640=0

    b=20

    a = 2 (20) + 8 = 48

    48+20+52 = 120
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