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14 September, 09:55

The sequence 12, 15, 18, 21, 51, 81, ... consists of all positive multiples of 3 that contain at least one digit that is a 1. What is the 50th term of the sequence? (2006 National Target #5)

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  1. 14 September, 10:15
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    159

    Step-by-step explanation:

    Using the formula for arithmetic progression,

    an = a + (n - 1) d

    Where a is the first term

    n is the number of terms or nothing term

    d is the common difference.

    From the question:

    a = 12

    d = 3

    nth = 50

    an = 12 + (50 - 1) 3

    = 12 + (49) 3

    = 12 + 147

    = 159
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