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17 July, 15:59

Find the 6th term of the geometric sequence, given the first term and common ratio a1 = 5 and r=3/2

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  1. 17 July, 16:25
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    Answer

    37.96875

    Explanation

    In geometric sequence we use the formula below to find the nth of a sequence.

    Tn = ar⁽ⁿ⁻¹⁾

    Where a ⇒ first term

    n ⇒ the term we are looking for

    T₆ = 5 * (3/2) ⁶⁻¹

    = 5 * (3/2) ⁵

    = 5 * 243/32

    = 1215/32

    = 37 31/32

    = 37.96875
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