How many milligrams of CO exist in 12000 liters of air with 10 ppm of CO?

1.2 * 10^4

12 * 10^3

12 * 10^5

12 * 10^4

D) 12000 liter of air contains CO = 12 x 10⁴ mg

Step-by-step explanation:

This is a simple unit conversion problem. What you need to know is what is the equivalent of parts per million (ppm) in mg per liter.

The relation is:

1 ppm = 1 milligram per liter

So,

10 ppm of CO in air means 10 mg of CO is present in 1 liter air.

1 liter of air contains CO = 10 mg

Multiply both sides by 12000, we get:

12000 liter of air contains CO = 10 x 12000 mg

12000 liter of air contains CO = 120000 mg

12000 liter of air contains CO = 1.2 x 10⁵ mg

12000 liter of air contains CO = 12 x 10⁴ mg