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16 February, 15:27

If you're using the inspection method, what constant term would you need in the numerator of this rational expression for (x+5) to be a common factor? (x^2+6x+14) / (x+5)

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  1. 16 February, 15:46
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    If I am using the inspection method, the constant term that I would need in the numerator of this rational expression for (x+5) to be a common factor of (x^2+6x+14) / (x+5) is 11 / (x+1)
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