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9 April, 12:38

If f (x) = 3x^2+1 and g (x) = 1-x, what is the truly value of (f-g) (2)

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  1. 9 April, 12:58
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    14

    Step-by-step explanation:

    f (x) = 3x²+1

    f (2) = 3 x 2² + 1 = 13

    g (x) = 1-x

    g (2) = 1 - 2 = - 1

    (f-g) (2) f (2) - g (2) = 13 - (-1) = 14
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