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28 August, 10:53

If G (x) = 3x+1, then G^-1 (1) is?

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  1. 28 August, 11:17
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    First you change x and y

    => x = 3y - 5

    Then you solve for y:

    x+5 = 3y / : 3

    y = g^ (-1) (x) = (1/3) x + (5/3)
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