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Jingles
Mathematics
25 January, 19:16
Evaluate - u2v3 when u=4 and v=-2
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Babs
25 January, 19:30
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First lets substitute the values: - 4x2x-2x3
Now lets solve: - 4 times 2 is - 8. Now - 8 times - 2 is 16 because a negative times a negative is a positive. The last step is to do 16 times 3 which is forty-eight.
Final Answer: When u=4 and v=-2 the equation is 48.
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