What is the solution set of 4x^2 - 36 = 0?

4x^2 - 36 = 0 (Original equation)

4x^2 = 36 (Add 36 to both sides)

x^2 = 9 (Divide by 4 on both sides)

x = 3, - 3 (Take the square root of 9)

Solution set: { + 3, - 3 } answer is x = + 3, x = - 3

Add 36 to both sides and divide by 4

and take its square root the answer is = 3