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Nathalie Warner
Mathematics
16 December, 16:41
Find the first derivative of y = sin^2 (cos2x)
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Octavio Bradford
16 December, 16:49
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Hello,
y=sin² (cos (2x))
y'=2*sin (cos (2x)) * cos (cos (2x)) * (-sin (2x) * 2)
= - 4*sin (cos (2x)) * cos (cos (2x)) * sin (2x)
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