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10 January, 01:27

The weather in a certain locale consists of alternating wet and dry spells. Suppose that the number of days in each rainy spell is a Poisson distribution with mean 2, and that a dry spell follows a geometric distribution with mean 7. Assume that the successive durations of rainy and dry spells are independent. What is the long-run fraction of time that it rains?

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  1. 10 January, 01:39
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    2/9

    Step-by-step explanation:

    The Poisson's distribution is a discrete probability distribution. A discrete probability distribution means that the events occur with a constant mean rate and independently of each other. It is used to signify the chance (probability) of a given number of events occurring in a fixed interval of time or space.

    In the long run, fraction of time that it rains = E (Number of days in rainy spell) / {E (Number of days in a rainy spell) + E (Number of days in a dry spell) }

    E (Number of days in rainy spell) = 2

    E (Number of days in a dry spell) = 7

    In the long run, fraction of time that it rains = 2 / (2 + 7) = 2/9
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