The probability that you roll a 3 on a six-sided die is. The probability that you flip a coin that lands on tails is. The probability that you roll a 3 on a six-sided die and you flip a coin that lands on tails is. What is the probability of flipping a coin and it landing on tails, given that you rolled a 3 on a six-sided die? Are these two events independent? P (T|3) =; therefore, events are independent because P (T|3) = P (T). P (T|3) =; therefore, events are dependent because P (T|3) ≠ P (T). P (T|3) =; therefore, events are dependent because P (T|3) ≠ P (T). P (T|3) =; therefore, events are independent because P (T|3) = P (T).

Question

Jaiden Hood

Mathematics

18 October, 04:33

The probability that you roll a 3 on a six-sided die is. The probability that you flip a coin that lands on tails is. The probability that you roll a 3 on a six-sided die and you flip a coin that lands on tails is. What is the probability of flipping a coin and it landing on tails, given that you rolled a 3 on a six-sided die? Are these two events independent? P (T|3) =; therefore, events are independent because P (T|3) = P (T). P (T|3) =; therefore, events are dependent because P (T|3) ≠ P (T). P (T|3) =; therefore, events are dependent because P (T|3) ≠ P (T). P (T|3) =; therefore, events are independent because P (T|3) = P (T).

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Nora Doyle · Answer 1

1/6; 1/2; 1/12; P (T|3) = 1/2; therefore, events are independent because P (T|3) = P (T).

Step-by-step explanation:

The probability of rolling a 3 on a six-sided die is 1/6. This is because there is one 3 out of 6 possibilities.

The probability of flipping a coin on tails is 1/2. This is because there is one side "tails" out of 2 possibilities.

The probability of rolling a 3 and flipping tails is 1/6 (1/2) = 1/12.

P (T|3) = P (3 and Tails) / P (3) = 1/12 / (1/6) = 1/12 (6/1) = 6/12 = 1/2

Since P (T|3) = P (3), these are independent events.