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12 July, 08:44

Find the second term of the arithmetic series described by a1=0.25, an=4, and sn=8.5 answer: a2=

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  1. 12 July, 09:03
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    Step-by-step explanation:

    an=4=a1 + (n-1) * d=0.25 + (n-1) * d

    so (n-1) * d=4-0.25=3.75

    Sn=a1*n + (n-1) * d

    a1*n+3.75=8.5

    0.25*n+3.75=8.5

    -3.75 - 3.75

    0.25*n=8.5-3.75=4.75

    n=4.75:0.25

    n=19

    so a19=a1 + (19-1) * d=4

    0.25+18*d=4

    -0.25 - 0.25

    18*d=3.75

    d=3.75/18

    d=0.208

    so a2=a1+0.208=0.25+0.208=0.458

    a2=0.458
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