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Mathematics
7 June, 07:28
Solve for x. x = log44
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Leland Moran
7 June, 07:44
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First, set the equation in exponential form.
x=logbY to b^x=Y
x=log44. so x=x, b=10, Y=44
10^x=44
I know that 10^1=10, 10^2=100, and 10^1.5=31.6 so x should be between 1.5 and 2.
The answer is x=1.64.
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